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Mesaj |
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Postati aici intrebari legate de problemele din aceasta varianta.
--- Pitagora,
Pro-Didactician
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1 c) stie careva??
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in Z6
1^2008=1
2*2*2=2 =>2^2008=(2^2007)*2=2*2=4
3*3=3 => 3^2008=3
4*4=4 => 4^2008=4
5*5=1 => 5^2008=1
1^2008+2^2008+3^2008+4^2008+5^2008=1+4+3+4+1=1
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